2015年2月28日 星期六

[UVA] 11547 - Automatic Answer

#include<bits/stdc++.h>
using namespace std;
int main(){
    int t,n;
    scanf("%d",&t);
    while(t--){
        scanf("%d",&n);
        n=(n*567/9+7492)*235/47-498;
        if(n<0) n*=-1;
        printf("%d\n",n/10%10);
    }
}

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